General Requirement Solve Hand Try Solve Without Using Compiler Q43894702
General requirement is to solve by hand and try to solve withoutusing a compiler
2. This problem relies on the following struct definition: typedef struct Employee char *first; // Employee’s first name. char *last; // Employee’s last name. int ID; // Employee ID. } Employee; Consider the following function, which takes three arrays – each of length n-containing the first names, last names, and ID numbers of n employees for some company. The function dynamically allocates an array of n Employee structs, copies the information from the array arguments into the corresponding array of structs, and returns the dynamically allocated array. Employee *makeArray(char **firstNames, char **lastNames, int *IDs, int n) int i; Employee *array= for (i = 0; i<n; i++) __malloc array[i].first = malloc array[i].last = malloc strcpy(array[i].first, firstNames[i]); strcpy(array[i].last, lastNames[i]); array[i].ID = IDs[i]; return array: a) Fill in the blanks above with the appropriate arguments for each malloc statement. b) Next, write a function that takes a pointer to the array created by the makeArray function, along with the number of employee records in that array (n) and frees all the dynamically allocated memory associated with that array. The function signature is as follows: void freeEmployeeArray(Employee *array, int n) Show transcribed image text 2. This problem relies on the following struct definition: typedef struct Employee char *first; // Employee’s first name. char *last; // Employee’s last name. int ID; // Employee ID. } Employee; Consider the following function, which takes three arrays – each of length n-containing the first names, last names, and ID numbers of n employees for some company. The function dynamically allocates an array of n Employee structs, copies the information from the array arguments into the corresponding array of structs, and returns the dynamically allocated array. Employee *makeArray(char **firstNames, char **lastNames, int *IDs, int n) int i; Employee *array= for (i = 0; i
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