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Think Through The Following Proof: We Will Show That Any Simple Graph Where Every Vertex Has Degree At Least 1 Is Connected. As A Base Case, We Have Two Vertices Connected By A Single Edge. Now, Suppose That For N ≤ K, A Simple Graph With N Vertices, Each Of Which Has Degree At Least 1, Is Connected. Consider A Simple Graph G With K Vertices, Each Of Which

Think Through The Following Proof: We Will Show That Any Simple Graph Where Every Vertex Has Degree At Least 1 Is Connected. As A Base Case, We Have Two Vertices Connected By A Single Edge. Now, Suppose That For N ≤ K, A Simple Graph With N Vertices, Each Of Which Has Degree At Least 1, Is Connected. Consider A Simple Graph G With K Vertices, Each Of Which

Think through the following proof: We will show that any simple graph where every vertex has degree at least 1 is connectedAs a base casewe have two vertices connected by a single edgeNowsuppose that for n ≤ ka simple graph with n verticeseach of which has degree at least 1is connectedConsider a simple graph G with k verticeseach of which has degree at least 1By the inductive hypothesisit is connectedAdd a vertex v to G so that we have G-with-vwhich has k + 1 vertices; in order that every vertex has degree at least 1we also have to add an edge to vBut an edge in a simple graph must connect two verticesso the other end of the edge must be incident to a vertex of GThusG-with-v is connected. What’s wrong with this proof? It can’t be right—consider the graph in Figure 4.11.

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