(Solved) : Part 1 Evaluate Expression Modify Code Add Operators Exponent Modulus Example 3 2 9 3 2 1 Q38174741 . . .
Part 1: (Evaluate expression)
Modify code below to add operators ^ forexponent and % for modulus.
For example, 3 ^ 2 is 9 and 3% 2 is 1.
The ^ operator has the highest precedence andthe % operator has the same precedence as the* and / operators. Your programshould prompt the user to enter an expression.
- Sample output:
package Collection_Ch20;
import java.util.Stack;
public class EvaluateExpression {
public static void main(String[] args) {
// Check number of argumentspassed
if (args.length != 1) {
System.out.println(“Usage: java EvaluateExpression”expression””);
System.exit(1);
}
try {
System.out.println(evaluateExpression(args[0]));
}
catch (Exception ex) {
System.out.println(“Wrong expression: ” + args[0]);
}
}
/** Evaluate an expression */
public static int evaluateExpression(Stringexpression) {
Stack<Integer> operandStack =new Stack<>();
Stack<Character>operatorStack = new Stack<>();
// Insert blanks around (, ), +,-, /, and *
expression =insertBlanks(expression);
// Extract operands andoperators
String[] tokens =expression.split(” “);
// Phase 1: Scan tokens
for (String token: tokens) {
if(token.length() == 0) // Blank space
continue; // Back to the while loop to extractthe next token
else if(token.charAt(0) == ‘+’ || token.charAt(0) == ‘-‘) {
// Process all +, -, *, / in the top of theoperator stack
while (!operatorStack.isEmpty() &&
(operatorStack.peek() == ‘+’|| operatorStack.peek() == ‘-‘ ||
operatorStack.peek() == ‘*’|| operatorStack.peek() == ‘/’ )) {
processAnOperator(operandStack, operatorStack);
}
// Push the + or – operator into the operatorstack
operatorStack.push(token.charAt(0));
}
else if(token.charAt(0) == ‘*’ || token.charAt(0) == ‘/’ ) {
// Process all *, / in the top of the operatorstack
while (!operatorStack.isEmpty() &&
(operatorStack.peek() == ‘*’|| operatorStack.peek() == ‘/’)) {
processAnOperator(operandStack, operatorStack);
}
// Push the * or / or % operator into theoperator stack
operatorStack.push(token.charAt(0));
}
else if(token.trim().charAt(0) == ‘(‘) {
operatorStack.push(‘(‘); // Push ‘(‘ tostack
}
else if(token.trim().charAt(0) == ‘)’) {
// Process all the operators in the stack untilseeing ‘(‘
while (operatorStack.peek() != ‘(‘) {
processAnOperator(operandStack, operatorStack);
}
operatorStack.pop(); // Pop the ‘(‘ symbol fromthe stack
}
else { // Anoperand scanned
// Push an operand to the stack
operandStack.push(new Integer(token));
}
}
// Phase 2: Process all theremaining operators in the stack
while (!operatorStack.isEmpty()){
processAnOperator(operandStack, operatorStack);
}
// Return the result
return operandStack.pop();
}
/** Process one operator: Take an operator fromoperatorStack and
/ * apply it on the operands in the operandStack*/
public static voidprocessAnOperator(Stack<Integer> operandStack,Stack<Character> operatorStack) {
char op =operatorStack.pop();
int op1 = operandStack.pop();
int op2 = operandStack.pop();
if (op == ‘+’)
operandStack.push(op2 + op1);
else if (op == ‘-‘)
operandStack.push(op2 – op1);
else if (op == ‘*’)
operandStack.push(op2 * op1);
else if (op == ‘/’)
operandStack.push(op2 / op1);
}
public static String insertBlanks(String s) {
String result = “”;
for (int i = 0; i <s.length(); i++) {
if (s.charAt(i)== ‘(‘ || s.charAt(i) == ‘)’ ||
s.charAt(i) == ‘+’ || s.charAt(i) == ‘-‘||
s.charAt(i) == ‘*’ || s.charAt(i) == ‘/’ )
result += ” ” + s.charAt(i) + ” “;
else
result += s.charAt(i);
}
return result;
}
}
Expert Answer
Answer to Part 1 Evaluate Expression Modify Code Add Operators Exponent Modulus Example 3 2 9 3 2 1 Q38174741 . . .
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