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(Solved) : Given Packet Capture Following Scan Nmap Sx 192 168 1 55 P22 80 445 45 33105540 192168111 Q30757157 . . .

Given a packet capture of the following scan: nmap -sx 192. 168 . 1 55 -p22, 80, 445 45 33.105540 192.168.1.115 192. 168. 1. 55 Tep 54 39007-> so tri, PSH, ORGI seas i win-1024 Orga0 Lena。 46 33.10659s 192.168.1.115 192.168.1.55 TCP 54 39007 445 [FIN, PSH, URGI seq1 win 1024 Urg-o Len-o 47 33.107672 192.168.1-115 192.168.1.55 TCP 54 39007 22 [FIN, P URG] Seq-1 win-1024 Urg o Len o 48 33.108730 192.168.1.55 192.168.1.115 TCP 54 44539007 [RST, ACK] 8eq-1 Ack 2 win o Len-o 49 33.108972 192-168.1.55 192-168 . 1.115 Tep 54 22-> 35007 rpgr, Aerl aeg-1 Aek-2 xǐn.0 ten-O 50 34.207377 192.160.1.115 192 .168.1.55 TCp 54 39008-> 80 [FIN, Ран, URG) ฮeq” 1 win-102 4 Urg”0 Lenno Which of the following should MOST likely be inferred based on the scan’s output? 192.168 1.115 is hosting a web server 192.168.1.55 is hosting a web server 192.168.1.55 is a Linux server 192 168.1.55 is a fle server ов. O D Show transcribed image text

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Answer to Given Packet Capture Following Scan Nmap Sx 192 168 1 55 P22 80 445 45 33105540 192168111 Q30757157 . . .