(Solved) : C Int Leftovercandycane Int N Int P 0 Int Q 0 P 18 N N P 2 Q 0 P Int R 1 R Q R R 3 Q Retur Q43922732 . . .
(c) int leftovercandycane (int n) { int p 0; int q = 0; while (p < 18 * n * n) { if (p % 2 q++; 0) { p++; for (int r = 1; r < q; r = r * 3) { q++; return p * q; Return value for (c): Running time of (c): Show transcribed image text (c) int leftovercandycane (int n) { int p 0; int q = 0; while (p
Expert Answer
Answer to (c) int leftovercandycane (int n) { int p 0; int q = 0; while (p < 18 * n * n) { if (p % 2 q++; 0) { p++; for (int r = 1...
OR