(Solved) : 16 Six Strings Following Fitness Function Values 5 10 15 25 50 100 Roulette Wheel Selectio Q44091836 . . .
I just need 1.7 and 1.8
1.6. Six strings have the following fitness function values: 5, 10, 15, 25, 50, 100. Under roulette wheel selection, calculate the expected number of copies of each string in the mating pool if a constant population size, 1 6 , is maintained. 1.7. Instead of using roulette wheel selection during reproduction, suppose we define a copy count for each string, ncount, as follows: nicount, – W/ where is the fitness of the ith string and is the average fitness of the population. The copy count is then used to generate the number of members of the mating pool by giving the integer part of nicount, copies to the ith string and an additional copy with probability equal to the fractional part of nicount, For example, with 100 and / -80, string / would receive an nicount, of 1.25, and thus would receive one copy with probability 1.0 and another copy with probability 0.25 Using the string fitness values in Problem 1.6, calculate the expected number of copies for each of the six strings. Calculate the total number of strings expected in the gene pool under this form of reproduction. 1.8. The form of reproduction discussed in Problem 1.7 is sometimes called reproduction with expected number control. In a short essay, explain why this is so. In what ways are roulette wheel selection and expected number control sim ilar? In what ways are they different? Show transcribed image text 1.6. Six strings have the following fitness function values: 5, 10, 15, 25, 50, 100. Under roulette wheel selection, calculate the expected number of copies of each string in the mating pool if a constant population size, 1 6 , is maintained. 1.7. Instead of using roulette wheel selection during reproduction, suppose we define a copy count for each string, ncount, as follows: nicount, – W/ where is the fitness of the ith string and is the average fitness of the population. The copy count is then used to generate the number of members of the mating pool by giving the integer part of nicount, copies to the ith string and an additional copy with probability equal to the fractional part of nicount, For example, with 100 and / -80, string / would receive an nicount, of 1.25, and thus would receive one copy with probability 1.0 and another copy with probability 0.25 Using the string fitness values in Problem 1.6, calculate the expected number of copies for each of the six strings. Calculate the total number of strings expected in the gene pool under this form of reproduction. 1.8. The form of reproduction discussed in Problem 1.7 is sometimes called reproduction with expected number control. In a short essay, explain why this is so. In what ways are roulette wheel selection and expected number control sim ilar? In what ways are they different?
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Answer to 1.6. Six strings have the following fitness function values: 5, 10, 15, 25, 50, 100. Under roulette wheel selection, cal…
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