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Ruby Pigeondata Color Purple Theo Peter Jr Lucky Grey Theo Peter Jr Ms K White Queenie And Q43892326

RUBY!

1. pigeon_data = {
2. :color => {
3. :purple => [“Theo”, “Peter Jr.”, “Lucky”],
4. :grey => [“Theo”, “Peter Jr.”, “Ms. K”],
5. :white => [“Queenie”, “Andrew”, “Ms. K”, “Alex”],
6. :brown => [“Queenie”, “Alex”]
7. },
8. :gender => {
9. :male => [“Alex”, “Theo”, “Peter Jr.”, “Andrew”,”Lucky”],
10. :female => [“Queenie”, “Ms. K”]
11. },
12. :lives => {
13. “Subway” => [“Theo”, “Queenie”],
14. “Central Park” => [“Alex”, “Ms. K”, “Lucky”],
15. “Library” => [“Peter Jr.”],
16. “City Hall” => [“Andrew”]
17. }
18. }

The data above is organized by attributes – :color, :gender, and:lives, each a hash. Within these hashes are arrays of pigeonnames.

We want this data, but in a different structure. Rather thansorting by attributes, your task is to create a hash wherepigeon names are the keys, with each name pointing to ahash of their attributes.

Expert Answer

Answer to RUBY! pigeon_data = { :color => { :purple => [“Theo”, “Peter Jr.”, “Lucky”], :grey => [“Theo”, “Peter Jr.”, “Ms. K”], :…