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Q2 Answer Bart B Program Finaltwoone Answer Bart C D Program Finaltwotwo Nr 55 66 77 88 99 Q43837151

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Q2) answer of bart a and b from program (finaltwoone) answer of bart c and d from program (finaltwotwo) Nr=5.5 , 6.6 , 7.7, 8

(finaltwoone)

clear m=1500; g=9.81; crr=0.008; cd=0.25; A=1.5; alfa=0; Fm=10; delt=0.005; v(1)=0; Tsim=30; T(1)=0; N(1)=0; Nr=5.5; r=0.3; f

(finaltwotwo)

clear m=1500; g=9.81; crr=0.008; cd=0.25; A=1.5; alfa=0; Fm=10; delt=0.005; v(1)=0; Tsim=30; T(1)=0; N(1)=0; Nr=8.8; r=0.3; f

Q2) answer of bart a and b from program (finaltwoone) answer of bart c and d from program (finaltwotwo) Nr=5.5 , 6.6 , 7.7, 8.8, 9.9 A)which Nr should be used toget fastest acceleration ? B)0 to 100Km/h , t=? C)which Nr should be used toget max speed? D) what is that speed (Vmax) ? clear m=1500; g=9.81; crr=0.008; cd=0.25; A=1.5; alfa=0; Fm=10; delt=0.005; v(1)=0; Tsim=30; T(1)=0; N(1)=0; Nr=5.5; r=0.3; for k=1:Tsim/delt Fr(k)=m*g*crr*(1+v(k)/44.7) +0.5*cd*A*v(k)*v(k) +m*g*sin(alfa/180*3.14); if N(K)>=0 & N(K)<1278 Tm(k)=255; elseif N(k)>=1278 & N(k)<1899.5 Tm(k)=-0.13*N(K)+422.9; elseif N(k)>=1899.5 & N(k) <2648.4 Tm(k)=-0.07*N(k)+307.6; elseif N(k)>=2648.4 & N(k)<3296.8 Tm(k)=-0.04*N(k)+229; elseif N(K)>=3296.8 & N(k)<4456.6 Tm(k)=-0.02*N(k)+160.6; elseif N(K)>=4456.6 & N(k) <6036.5 Tm(k)=-0.012*N(k)+125.2; elseif N(k)>=6036.5 & N(K)<10255.7 Tm(k)=-0.005*N(k)+81.2; elseif N(k)>=10255.7 & N(k) <10675.8 Tm(k)=-0.07*N(k)+747.3; else Tm(k)=0; end Fm(k)=Tm(k)*Nr/r; a(k)=[Fm(k)-Fr(k)]/m; v(k+1)=v(k)+a(k)*delt; N(k+1)=v(k+1)/(2*3.14*r)*60*Nr; T(k+1)=T(k)+delt; end plot(T,V*3.6) clear m=1500; g=9.81; crr=0.008; cd=0.25; A=1.5; alfa=0; Fm=10; delt=0.005; v(1)=0; Tsim=30; T(1)=0; N(1)=0; Nr=8.8; r=0.3; for k=1:Tsim/delt Fr(k)=m*g*crr*(1+v(k)/44.7) +0.5*cd*A*v(k)*v(k) +m*g*sin(alfa/180*3.14); if N(k)>=0 & N(k)<2438.4 Tm(k)=-0.002*N(k)+104.5; elseif N(k)>=2438.4 & N(K)<3808.2 Tm(k)=-0.023*N(k)+154.9; elseif N(k)>=3808.2 & N(k) <6410.96 Tm(k)=-0.01*N(k)+99.4; elseif N(K)>=6410.96 & N(K)<9004.6 Tm(k)=-0.009*N(k)+91.8; elseif N(K)>=9004.6 & N(k)<9415.5 Tm(k)=-0.03*N(k)+282.5; else Tm(k)=0; end Fm(k)=Tm(k)*Nr/r; a(k)=[Fm(k)-Fr(k)]/m; v(k+1)=v(k)+a(k)*delt; N(k+1)=v(k+1)/(2*3.14*r)*60*Nr; T(k+1)=T(k)+delt; end plot(t,v*3.6) Show transcribed image text Q2) answer of bart a and b from program (finaltwoone) answer of bart c and d from program (finaltwotwo) Nr=5.5 , 6.6 , 7.7, 8.8, 9.9 A)which Nr should be used toget fastest acceleration ? B)0 to 100Km/h , t=? C)which Nr should be used toget max speed? D) what is that speed (Vmax) ?
clear m=1500; g=9.81; crr=0.008; cd=0.25; A=1.5; alfa=0; Fm=10; delt=0.005; v(1)=0; Tsim=30; T(1)=0; N(1)=0; Nr=5.5; r=0.3; for k=1:Tsim/delt Fr(k)=m*g*crr*(1+v(k)/44.7) +0.5*cd*A*v(k)*v(k) +m*g*sin(alfa/180*3.14); if N(K)>=0 & N(K)=1278 & N(k)=1899.5 & N(k) =2648.4 & N(k)=3296.8 & N(k)=4456.6 & N(k) =6036.5 & N(K)=10255.7 & N(k) =0 & N(k)=2438.4 & N(K)=3808.2 & N(k) =6410.96 & N(K)=9004.6 & N(k)

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Answer to Q2) answer of bart a and b from program (finaltwoone) answer of bart c and d from program (finaltwotwo) Nr=5.5 , 6.6 , 7…

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