Q1 Answer Bart B Program Finaloneone Answer Bart C D Program Finalonetwo Nr 55 66 77 88 99 Q43837285
MATLAP Language
(finaloneone)
(finalonetwo)
Q1) answer of bart a and b from program (finaloneone) answer of bart c and d from program (finalonetwo) Nr=5.5 , 6.6 , 77, 8.8 , 9.9 A) which Nr should be used toget fastest acceleration ? B)0 to 100Km/h , t=? C)which Nr should be used toget max speed? D)what is that speed (Vmax) ? clear m=1500; g=9.81; crr=0.008; cd=0.25; A=1.5; alfa=0; Fm=10; delt=0.005; v(1)=0; Tsim=30; T(1)=0; N(1)=0; Nr=5.5; r=0.3; for k=1:Tsim/delt Fr(k)=m*g*crr*(1+v(k)/44.7) +0.5*cd*A*v(k)*v(k) +m*g*sin(alfa/180*3.14); if elseif N(k)>=0 & N(k)<3963 Tm(k)=255; elseif N(k)>=3963 & N(k)<4589.87 Tm(k)=-0.03*N(k)+374.4; elseif N(K)>=4589.87 & N(k)<5456.2 Tm(k)=-0.05*N(K)+463.39; elseif N(k)>=5456.2 & N(K)<6930.88 Tm(k)=-0.03*N(k)+353.9; elseif N(K)>=6930.88 & N(k)<8525.35 Tm(k)=-0.02*N(k)+283.8; elseif N(k)>=8525.35 & N(K)<10322.6 Tm(k)=-0.01*N(k)+196.1; elseif N(k)>=10322.6 & N(k) <10792.63 Tm(k)=-0.19*N(k)+2126.15; else Tm(k)=0; end Fm(k)=Tm(k)*Nr/r; a(k)=[Fm(k)-Fr(k)]/m; v(k+1)=v(k)+a(k)*delt; N(k+1)=v(k+1)/(2*3.14*r)*60*Nr; T(k+1)=T(k)+delt; end plot(T,V* 3.6) clear m=1500; g=9.81; crr=0.008; cd=0.25; A=1.5; alfa=0; Fm=10; delt=0.005; v(1)=0; Tsim=30; T(1)=0; N(1)=0; Nr=5.5; r=0.3; for k=1:Tsim/delt Fr(k)=m*g*crr*(1+v(k)/44.7) +0.5*cd*A*v(k)*v(k) +m*g*sin(alfa/180*3.14); if N(K)>=0 & N(k) <2000 Tm(k)=-0.001*N(k)+104.8; elseif N(k)>=2000 & N(k)<8470 Tm(k)=-0.005*N(k)+113.97; elseif N(k)>=8470 & N(k)<10506.9 Tm(k)=-0.07*N(k)+130.6; elseif N(k)>=10506.9 & N(k)<10792.63 Tm(k)=-0.199*N(k)+2147.7; else Tm(k)=0; end Fm(k)=Tm(k)*Nr/r; a(k)=[Fm(k)-Fr(k)]/m; v(k+1)=v(k)+a(k)*delt; N(k+1)=v(k+1)/(2*3.14*r)*60*Nr; T(k+1)=T(k)+delt; end plot(t,v* 3.6) Show transcribed image text Q1) answer of bart a and b from program (finaloneone) answer of bart c and d from program (finalonetwo) Nr=5.5 , 6.6 , 77, 8.8 , 9.9 A) which Nr should be used toget fastest acceleration ? B)0 to 100Km/h , t=? C)which Nr should be used toget max speed? D)what is that speed (Vmax) ?
clear m=1500; g=9.81; crr=0.008; cd=0.25; A=1.5; alfa=0; Fm=10; delt=0.005; v(1)=0; Tsim=30; T(1)=0; N(1)=0; Nr=5.5; r=0.3; for k=1:Tsim/delt Fr(k)=m*g*crr*(1+v(k)/44.7) +0.5*cd*A*v(k)*v(k) +m*g*sin(alfa/180*3.14); if elseif N(k)>=0 & N(k)=3963 & N(k)=4589.87 & N(k)=5456.2 & N(K)=6930.88 & N(k)=8525.35 & N(K)=10322.6 & N(k) =0 & N(k) =2000 & N(k)=8470 & N(k)=10506.9 & N(k)
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Answer to Q1) answer of bart a and b from program (finaloneone) answer of bart c and d from program (finalonetwo) Nr=5.5 , 6.6 , 7…
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