Python 3 Help Looking Coding Help Help Theory Pseudocode Understand Math Part Stuck Implem Q43908142
Python 3 help! Looking for coding help! Not help with theory orpseudocode! I understand the math part but am stuck on how toimplement it in Python! Using variables it runs great BUT if i tryto use set integers I can’t get the program to run properly.The issue is making groups of (i used n as a variable in thisexample) 3 with at least 1 man per group.So n=3 (groups of three people)k= 1 (number of men at a minimum)
m = total number of menw = total number if womenSo if there are 2 men and 2 women our groups will look likethis:m1w1w2m2w1w2m1m2w1m1m2w2
This seems easier when i just throw in variables, but how cani set n=3 and k=1 (min number of men) in the code? I’m just reallystuck on this one question to get python to run it in Jupyter! iknow theres probably an easy fix, to just havedef ways (w,m) run with set numbers for group size (n =3) andminimum number of men (k=1, 2, 3 depending on variable m).what would the code look like?
iwould like to print the number of combinations of teams of three ofmen and women with at least one man. im just getting stuck on howto set n=3 and k= at least 1
10:14 AA google.ca c geeksforgeeks.org Input: m = 2, w = 2, n = 3, k = 1 Output: 4 There are 2 men, 2 women. We need to make a team of size 3 with at least one man and one woman. We can make the team in following ways. mi m2 w1 mi wi w2 m2 w1 W2 mi m2 w2 Input: m = 7, W = 6, n = 5, k = 3 Output: 756 Input: m = 5, W = 6, n = 6, k = 3 Output: 281 Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: Since, we have to take at least k men. Totals ways = Ways when ‘k’ men are # Returns factorial of the number def fact (n) : fact = 1 for i in range (2, n + fact *= i return fact # Function to calculate ner def ncr in, r): ncr = fact (n) // (fact (r) * fact (n – r)) return ner # Function to calculate # the total possible ways def ways (m, w, n, k): ans = 0 while (m >= k): ans += ner (m, k) * ncr (w, n – k) k += 1 return ans; # Driver code m = 7 6. n = 5 k = 3 print (ways (m, w, n, k)) # Returns factorial of the number def fact (n) : fact = 1 for i in range (2, n + fact *= i return fact # Function to calculate ner def ncr in, r): ncr = fact (n) // (fact (r) * fact (n – r)) return ner # Function to calculate # the total possible ways def ways (m, w, n, k): ans = 0 while (m >= k): ans += ner (m, k) * ncr (w, n – k) k += 1 return ans; # Driver code m = 7 n = 5 k = 3 print (ways (m, w, n, k)) 10:14 AA google.ca c geeksforgeeks.org Input: m = 2, w = 2, n = 3, k = 1 Output: 4 There are 2 men, 2 women. We need to make a team of size 3 with at least one man and one woman. We can make the team in following ways. mi m2 w1 mi wi w2 m2 w1 W2 mi m2 w2 Input: m = 7, W = 6, n = 5, k = 3 Output: 756 Input: m = 5, W = 6, n = 6, k = 3 Output: 281 Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: Since, we have to take at least k men. Totals ways = Ways when ‘k’ men are Show transcribed image text 10:14 AA google.ca c geeksforgeeks.org Input: m = 2, w = 2, n = 3, k = 1 Output: 4 There are 2 men, 2 women. We need to make a team of size 3 with at least one man and one woman. We can make the team in following ways. mi m2 w1 mi wi w2 m2 w1 W2 mi m2 w2 Input: m = 7, W = 6, n = 5, k = 3 Output: 756 Input: m = 5, W = 6, n = 6, k = 3 Output: 281 Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: Since, we have to take at least k men. Totals ways = Ways when ‘k’ men are
# Returns factorial of the number def fact (n) : fact = 1 for i in range (2, n + fact *= i return fact # Function to calculate ner def ncr in, r): ncr = fact (n) // (fact (r) * fact (n – r)) return ner # Function to calculate # the total possible ways def ways (m, w, n, k): ans = 0 while (m >= k): ans += ner (m, k) * ncr (w, n – k) k += 1 return ans; # Driver code m = 7 6. n = 5 k = 3 print (ways (m, w, n, k))
# Returns factorial of the number def fact (n) : fact = 1 for i in range (2, n + fact *= i return fact # Function to calculate ner def ncr in, r): ncr = fact (n) // (fact (r) * fact (n – r)) return ner # Function to calculate # the total possible ways def ways (m, w, n, k): ans = 0 while (m >= k): ans += ner (m, k) * ncr (w, n – k) k += 1 return ans; # Driver code m = 7 n = 5 k = 3 print (ways (m, w, n, k))
10:14 AA google.ca c geeksforgeeks.org Input: m = 2, w = 2, n = 3, k = 1 Output: 4 There are 2 men, 2 women. We need to make a team of size 3 with at least one man and one woman. We can make the team in following ways. mi m2 w1 mi wi w2 m2 w1 W2 mi m2 w2 Input: m = 7, W = 6, n = 5, k = 3 Output: 756 Input: m = 5, W = 6, n = 6, k = 3 Output: 281 Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: Since, we have to take at least k men. Totals ways = Ways when ‘k’ men are
Expert Answer
Answer to Python 3 help! Looking for coding help! Not help with theory or pseudocode! I understand the math part but am stuck on h…
OR