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High Ascent Weather Balloon Shape Cone Polnting Downwards Cone Height Hand Hemispherical T Q43863982

A high ascent weather balloon is in the shape of cone polnting downwards. The cone has a height of Hand a hemispherical top o2- Show the final value of SurfaceArea using the builtin function disp() and do not show the result by avoiding the semicolonA high ascent weather balloon is in the shape of cone polnting downwards. The cone has a height of Hand a hemispherical top of a radius R. The surface area of the weather balloon is A = RR°(2+ V1+M²), and the volume is V = xR(2+ M)/3, M = H/R For a where weather balloon with a volume of 14000 m, the surface area as a function of M is shown below. 3600 3500 3400 3300 3200 3100 3000 2900 9. 1- Calculate the surface area of the balloon for given Vector M and volume V. Call the output variable SurfaceArea. (30 points) The output is a row array of surface areas. Restriction: For and while loops may not be used. Your code should be written based on Parameters and the value of parameters be assigned at the beginning of the code. For example: V-14000; M-[0:10]: (you can also look online and learn how to create a vector using linspace()) Then write your statements that calculates the surface from M and V. Surface Area m 2- Show the final value of SurfaceArea using the builtin function disp() and do not show the result by avoiding the semicolon at the end of the line. (10 points) 3- Assuming the value of surface area for M=1 is 100, then using the disp() function display the following output. You need to do indexing to find the correct value of SurfaceArea (10 points) “The surface area for the value of M-1 is: 100” Show transcribed image text A high ascent weather balloon is in the shape of cone polnting downwards. The cone has a height of Hand a hemispherical top of a radius R. The surface area of the weather balloon is A = RR°(2+ V1+M²), and the volume is V = xR(2+ M)/3, M = H/R For a where weather balloon with a volume of 14000 m, the surface area as a function of M is shown below. 3600 3500 3400 3300 3200 3100 3000 2900 9. 1- Calculate the surface area of the balloon for given Vector M and volume V. Call the output variable SurfaceArea. (30 points) The output is a row array of surface areas. Restriction: For and while loops may not be used. Your code should be written based on Parameters and the value of parameters be assigned at the beginning of the code. For example: V-14000; M-[0:10]: (you can also look online and learn how to create a vector using linspace()) Then write your statements that calculates the surface from M and V. Surface Area m
2- Show the final value of SurfaceArea using the builtin function disp() and do not show the result by avoiding the semicolon at the end of the line. (10 points) 3- Assuming the value of surface area for M=1 is 100, then using the disp() function display the following output. You need to do indexing to find the correct value of SurfaceArea (10 points) “The surface area for the value of M-1 is: 100”

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