General Requirement Solve Hand Try Solve Without Using Compiler 1 Would Output Following Q43895441
General requirement is to solve by hand and try tosolve without using any compiler.
1. What would be the output of the following?
a.
![int main() { char s[] = Da gaad feel gaad! ; char x = 0; char t[25] ; strcpy(t, s); int i=0; while ( s[i] != ) { if](https://media.cheggcdn.com/media/0fc/0fc771d4-30ca-4b2c-88a4-7b72469c93ae/image.png)
b.
![void encrypt(char A[][20], int cypher, int size) { for(int i = 0; i<size; i++) for(int j=0; A[i][j] != ; j++) A[i][j] = A](https://media.cheggcdn.com/media/aa5/aa56d6f7-7d1a-4086-b661-0cef72d7fa6c/image.png)
int main() { char s[] = “Da gaad feel gaad!” ; char x = ‘0’; char t[25] ; strcpy(t, s); int i=0; while ( s[i] != ‘ ‘ ) { if (t[i] == ‘a’) * (s+i) = x ; i++; printf(“n%s”, s return 0; void encrypt(char A[][20], int cypher, int size) { for(int i = 0; i<size; i++) for(int j=0; A[i][j] != ‘ ‘; j++) A[i][j] = A[i][j] + cypher; int main(void) { char arr[4][20] = { “ford”, “nissan”, “accura”, “audiº encrypt(arr, 2, 5); for(int i = 0; i<4; i++) { printf(“%sn”, arr[i]); return 0; Show transcribed image text int main() { char s[] = “Da gaad feel gaad!” ; char x = ‘0’; char t[25] ; strcpy(t, s); int i=0; while ( s[i] != ‘ ‘ ) { if (t[i] == ‘a’) * (s+i) = x ; i++; printf(“n%s”, s return 0;
void encrypt(char A[][20], int cypher, int size) { for(int i = 0; i
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Answer to General requirement is to solve by hand and try to solve without using any compiler. 1. What would be the output of the …
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