Finished 2 Im Confused 2b Need Use Loop Compare Different Frequencies Vo Reach Maximum Num Q43879264
I have finished 2.a), Im just confused with 2.b) we need to use afor loop to compare the different frequencies and Vo until we reachthe maximum number. I’ll include the code for 2.a)
# include <stdio.h>
# include <conio.h>
# include <math.h>
# define PI 3.14
int main() {
float L = 4.3e-4;
float C = 5.1e-6;
float R = 5;
float VI = 5;
float freq;
printf(“Enter the Frequency in Hz: “);
scanf_s(“%f”, &freq);
float XL = 2 * PI * freq * L;
float XC = 1 / (2 * PI * freq * C);
float VO = (VI * R) / sqrt((XL – XC) * (XL – XC) + R * R);printf(“The voltage of VO = %f “, VO);
_getch();
return 0;
}
2.2 (2 marks) (a). Create a C program to calculate the output voltage Vo of a RLC circuit according to the following formulas for different inputs of frequency, PI = 3.14 Vi= 5 volts L = 4.3e-4 Henrys C = 5. le-6 Farads R= 5 Ohms XL=2* P*f*L Xc = 1/(2* PI* f* C) Vo=(Vi* R/ sqrt(XL-Xc) * (XL-Xc) +R*R) Where XL = Inductive reactance in ohms. f Frequency in hertz. Xc = Capacitive reactance in ohms. Hint: include the math.h header file because the sqrt() fuction is needed (b). Change the above program to input different values of R and output the frequency f where Vo is maximum. Use frequencies from 10 to 1,000,000 Hertz with an increment of 10 Show transcribed image text 2.2 (2 marks) (a). Create a C program to calculate the output voltage Vo of a RLC circuit according to the following formulas for different inputs of frequency, PI = 3.14 Vi= 5 volts L = 4.3e-4 Henrys C = 5. le-6 Farads R= 5 Ohms XL=2* P*f*L Xc = 1/(2* PI* f* C) Vo=(Vi* R/ sqrt(XL-Xc) * (XL-Xc) +R*R) Where XL = Inductive reactance in ohms. f Frequency in hertz. Xc = Capacitive reactance in ohms. Hint: include the math.h header file because the sqrt() fuction is needed (b). Change the above program to input different values of R and output the frequency f where Vo is maximum. Use frequencies from 10 to 1,000,000 Hertz with an increment of 10
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