(Solved) : Gorst Two Pictures Top Problem Mext Two Pictures Bottom Problem Ate Answer Choices Q37209424 . . .
the gorst two pictures are of the top of the problem
the mext two pictures are the bottom of the problem
these ate the answer choices
MEM sub $11, $2, EX: and $12, $4, $5 ID: or $13, $6, $7 IF: and $14, $8, $9 EX/MEM ID/EX 10m 10 IF/ID O M 10 or 10 10 Add Add Branch ALU result shift, Left 2 $4 $6 Read data 1 Read 7Read HCRead address Reg. 1 Reg.2 ALU Registers ALU 5resut $7 Read data 2 이 Write Reg Data Memory Write data Instruction Memory MEM: sub $11, $2, $3 EX: and $12, $4, $5 WB lw $10, 20 ($1) ID/EX EX/MEM MEM/WB 10 10 10 Add ALU Branch Shift Left 2 $ 4 ALU 5 rosut Data Memory l: Attempt 1 1 X or 10 110 Add Add ALU result Shift Left 2 $6 $4 Read Read Reg. 1 data 1 Read address 7 Read Reg. Registers ALU 5resut 10 Write Read $ $5 Instruction Memory Write ata 2 32 Instructin16 ALU extend Clock 5 20-16 13 ALUOp tempt 1 or 10 10 Add ALU Branch Shiftresul Left 2 $4 ReadRead Reg. 1 Read data 1 Reg. 2 ALU Registers 1 M Address da ALUL $5resu 0 Write Read $ Reg data 2 Write 0 o x Data 8sign- 32 Instructoe16 extend ALU MemRead U 13 12 10 RegDst x 16 Sign. 32 extend ALU Control Clock 5 20-16 13 13 12 U 15-11 RegDst and instruction (and $12, $4, $5) executes the arithmetic logic operation with the data values stored in register $4 and $5 and instruction (and $14, $8, $9) starts to interprets the contents of the instruction. lw instruction (Iw $10, 20($1) already accessed the data memory. It loads the accessed data into the register sub instruction (sub $11, $2. $3) already finished the arithmetic logic operation. It stores the result in the data memory Submit Quiz I of 4 questions saved 5 9 Show transcribed image text MEM sub $11, $2, EX: and $12, $4, $5 ID: or $13, $6, $7 IF: and $14, $8, $9 EX/MEM ID/EX 10m 10 IF/ID O M 10 or 10 10 Add Add Branch ALU result shift, Left 2 $4 $6 Read data 1 Read 7Read HCRead address Reg. 1 Reg.2 ALU Registers ALU 5resut $7 Read data 2 이 Write Reg Data Memory Write data Instruction Memory
MEM: sub $11, $2, $3 EX: and $12, $4, $5 WB lw $10, 20 ($1) ID/EX EX/MEM MEM/WB 10 10 10 Add ALU Branch Shift Left 2 $ 4 ALU 5 rosut Data Memory
l: Attempt 1 1 X or 10 110 Add Add ALU result Shift Left 2 $6 $4 Read Read Reg. 1 data 1 Read address 7 Read Reg. Registers ALU 5resut 10 Write Read $ $5 Instruction Memory Write ata 2 32 Instructin16 ALU extend Clock 5 20-16 13 ALUOp
tempt 1 or 10 10 Add ALU Branch Shiftresul Left 2 $4 ReadRead Reg. 1 Read data 1 Reg. 2 ALU Registers 1 M Address da ALUL $5resu 0 Write Read $ Reg data 2 Write 0 o x Data 8sign- 32 Instructoe16 extend ALU MemRead U 13 12 10 RegDst
x 16 Sign. 32 extend ALU Control Clock 5 20-16 13 13 12 U 15-11 RegDst and instruction (and $12, $4, $5) executes the arithmetic logic operation with the data values stored in register $4 and $5 and instruction (and $14, $8, $9) starts to interprets the contents of the instruction. lw instruction (Iw $10, 20($1) already accessed the data memory. It loads the accessed data into the register sub instruction (sub $11, $2. $3) already finished the arithmetic logic operation. It stores the result in the data memory Submit Quiz I of 4 questions saved 5 9
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