Need Help 2 Question Using Unix Operator Used Quickly Check Number Odd Even Value Expressi Q43893413
I need help with these 2 question using UNIX
- The & operator can be used to quickly check if anumber is odd or even. The value of expression (x & 1)would be non-zero only if x is odd, otherwise the value would bezero.
#include <stdio.h>
int main()
{
//User enters an integer number
// if x is even, print “even”, otherwise print “odd” using &operator
return 0;
}
Complete the aboveprogram and test it with 17, 19, 22, 100.
Your output :
3.
Suppose two integer values a and b
Perform, x = a ^ b
Now x ^ b will evaluateto a
and x ^ a will evaluate tob.
The following program is to swap two numbers using xoroperator.
/**
* C program to swap two numbers using bitwise operator
*/
#include <stdio.h>
int main()
{
int num1, num2;
/* Input two numbers from user */
printf(“Enter any two numbers: “);
scanf(“%d%d”, &num1, &num2);
printf(“Original value of num1 = %dn”,num1);
printf(“Original value of num2 = %dn”,num2);
/* Swap two numbers */
//Fill out the codes using xor operator
printf(“Num1 after swapping = %dn”,num1);
printf(“Num2 after swapping = %dn”,num2);
return 0;
}
Output with test case: 66, 22
Expert Answer
Answer to I need help with these 2 question using UNIX The & operator can be used to quickly check if a number is odd or even. The…
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